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Question Number 32159 by rahul 19 last updated on 20/Mar/18
Express the following in a+ib form:  (((cos x+isin x)(cos y+isin y))/((cosa+isin a)(cosb+isinb))).
Expressthefollowingina+ibform:(cosx+isinx)(cosy+isiny)(cosa+isina)(cosb+isinb).
Commented by abdo imad last updated on 20/Mar/18
E =((e^(ix)  e^(iy) )/(e^(ia)  e^(ib) )) =e^(i(x+y))  e^(−i(a+b)) =e^(i(x+y−a−b))   =cos(x+y−a−b) +i sin(x+y −a −b) .
E=eixeiyeiaeib=ei(x+y)ei(a+b)=ei(x+yab)=cos(x+yab)+isin(x+yab).
Commented by rahul 19 last updated on 20/Mar/18
thank you !
thankyou!
Answered by Tinkutara last updated on 20/Mar/18
=((e^(ix) e^(iy) )/(e^(ia) e^(ib) ))=e^(i(x+y−a−b))   =cos (x+y−a−b)+isin (x+y−a−b)
=eixeiyeiaeib=ei(x+yab)=cos(x+yab)+isin(x+yab)
Commented by rahul 19 last updated on 20/Mar/18
thank you !
thankyou!

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