f-100x-1-50x-1-2x-1-amp-f-1-3-p-p-

Question Number 102721 by bramlex last updated on 10/Jul/20

f (\frac{100 x - 1}{50 x + 1}) = 2 x - 1 & f^{- 1} (3) = p

p = ?

Commented by bramlex last updated on 10/Jul/20

f^{- 1} (3) = p \Leftrightarrow f (p) = 3

2 x - 1 = 3; x = 2 then p =

\frac{100.2 - 1}{50.2 + 1} = \frac{199}{101} ∙

Answered by mathmax by abdo last updated on 10/Jul/20

f (\frac{100 x - 1}{50 x + 1}) = 2 x - 1 \Rightarrow f^{- 1} (2 x - 1) = \frac{100 x - 1}{50 x + 1}

x = 2 \Rightarrow f^{- 1} (2.2 - 1) = \frac{200 - 1}{100 + 1} \Rightarrow f^{- 1} (3) = \frac{199}{101}