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f-continue-on-0-1-and-f-x-gt-0-on-0-1-prove-that-0-1-lnf-x-dx-ln-0-1-f-x-dx-

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Question Number 97983 by abdomathmax last updated on 10/Jun/20
f continue on [0,1] and f(x)>0 on [0,1] prove that ∫_0 ^1 lnf(x)dx≤ln(∫_0 ^1 f(x)dx)
fcontinueon[0,1]andf(x)>0on[0,1]provethat∫01lnf(x)dx⩽ln(∫01f(x)dx)

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