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f-is-a-function-that-assigns-to-each-natural-number-multiplication-of-its-digits-for-exampl-f-200-0-f-128-1-2-8-16-find-the-value-of-f-100-f-101-f-




Question Number 156775 by mnjuly1970 last updated on 15/Oct/21
     f  is  a function that assigns     to each natural number        multiplication of its digits       for exampl :  f( 200)=0      f ( 128 )=1×2×8 =16       find the value of :       f (100) + f(101 )+ f (102 )+...f(999)=?
fisafunctionthatassignstoeachnaturalnumbermultiplicationofitsdigitsforexampl:f(200)=0f(128)=1×2×8=16findthevalueof:f(100)+f(101)+f(102)+f(999)=?
Commented by Rasheed.Sindhi last updated on 15/Oct/21
Σ_(a=1,b=0,c=0) ^(a=9,b=9,c=9) abc=91125
a=9,b=9,c=9a=1,b=0,c=0abc=91125
Answered by Rasheed.Sindhi last updated on 15/Oct/21
100≤abc^(−) ≤999  c=0,1,2,...,9  ab0^(−) ,ab1^(−) ,ab2^(−) ,...ab9^(−)   f(ab0^(−) )+f(ab1^(−) )+f(ab2^(−) )+,...+f(ab9^(−) )  =a.b.0+a.b.1+a.b.2+...+a.b.9  =ab(0+1+2+3+...+9)  =ab(((9×10)/2))=ab(45)  b=0,1,2,...,9  a.b(45):   45a.0+45a.1+45a.2+...+45a.9  =45a(0+1+2+...+9)=45^2 a  a=1,2,3,...,9  45^2 a:  45^2 .1+45^2 .2+45^2 .3+...+45^2 .9  45^2 (1+2+3+...+9)=45^3 =91125         By my son, Arshad Soomro
100abc999c=0,1,2,,9ab0,ab1,ab2,ab9f(ab0)+f(ab1)+f(ab2)+,+f(ab9)=a.b.0+a.b.1+a.b.2++a.b.9=ab(0+1+2+3++9)=ab(9×102)=ab(45)b=0,1,2,,9a.b(45):45a.0+45a.1+45a.2++45a.9=45a(0+1+2++9)=452aa=1,2,3,,9452a:452.1+452.2+452.3++452.9452(1+2+3++9)=453=91125Bymyson,ArshadSoomro
Commented by mnjuly1970 last updated on 16/Oct/21
very nice thanks alot ...
verynicethanksalot
Commented by qaz last updated on 15/Oct/21
S=Σ_(a=1) ^9 Σ_(b=1) ^9 Σ_(c=1) ^9 abc=Σ_(a=1) ^9 aΣ_(b=1) ^9 bΣ_(c=1) ^9 c=(((9∙10)/2))^3 =91125
S=9a=19b=19c=1abc=9a=1a9b=1b9c=1c=(9102)3=91125

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