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f-x-2-x-2f-x-2-3x-2-9x-2-15x-then-what-is-the-value-of-f-10-




Question Number 23833 by Joel577 last updated on 07/Nov/17
f(x^2  + x) + 2f(x^2  − 3x + 2) = 9x^2  − 15x  then what is the value of f(10) ?
f(x2+x)+2f(x23x+2)=9x215xthenwhatisthevalueoff(10)?
Commented by prakash jain last updated on 07/Nov/17
x=0  f(0)+2f(2)=0  x=1  f(2)+2f(0)=−6  f(2)=2  f(0)=−4  f(x) is linear function  f(x)=ax+b  ⇒f(x)=3x−4  f(x^2 +x)+2f(x^2 −3x+2)=  =3(x^2 +x)−4+2[3(x^2 −3x+2)−4]  =3x^2 +3x−4+2(3x^2 −9x+2)  =9x^2 −15x  f(x)=3x−4  f(10)  =30−4=26
x=0f(0)+2f(2)=0x=1f(2)+2f(0)=6f(2)=2f(0)=4f(x)islinearfunctionf(x)=ax+bf(x)=3x4f(x2+x)+2f(x23x+2)==3(x2+x)4+2[3(x23x+2)4]=3x2+3x4+2(3x29x+2)=9x215xf(x)=3x4f(10)=304=26
Commented by ajfour last updated on 07/Nov/17
you make it easy enough sir!
youmakeiteasyenoughsir!
Commented by Joel577 last updated on 08/Nov/17
thank you very much
thankyouverymuch
Answered by kaivan.ahmadi last updated on 13/Dec/17
f(0)=−4   az the Mr parkash slution  if we set x^2 +x=10⇒  x^2 −3x+2=−4x+12  and  9x^2 −15x=−24x+90  Now replace  f(10)+2f(−4x+12)=−24x+90  and so for x=3 we have  f(10)+2f(0)=18⇒f(10)=26  in this way we didnt use the  linearly of   f.
f(0)=4aztheMrparkashslutionifwesetx2+x=10x23x+2=4x+12and9x215x=24x+90Nowreplacef(10)+2f(4x+12)=24x+90andsoforx=3wehavef(10)+2f(0)=18f(10)=26inthiswaywedidntusethelinearlyoff.
Commented by prakash jain last updated on 13/Dec/17
Thanks. It is a good approach.  Very useful when it is difficult  to evaluate f(x) in terms of x alone.
Thanks.Itisagoodapproach.Veryusefulwhenitisdifficulttoevaluatef(x)intermsofxalone.

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