Menu Close

f-x-3-f-x-2x-3-F-2-0-F-2-

Tinku Tara 0 Comments
Pin




Question Number 63485 by ANTARES VY last updated on 04/Jul/19
f(x−3)+f(x)=2x−3 F(2)=0. F(−2)=?
f(x−3)+f(x)=2x−3F(2)=0.F(−2)=?
Answered by MJS last updated on 04/Jul/19
f(x)=ax+b f(x−3)+f(x)=2x−3 2ax−3a+2b=2x−3 2a=2 −3a+2b=−3 ⇒ a=1∧b=0 f(x)=x F(x)=∫xdx=(x^2 /2)+c F(2)=0 ⇒ c=−2 F(x)=(x^2 /2)−2 F(−2)=0
f(x)=ax+bf(x−3)+f(x)=2x−32ax−3a+2b=2x−32a=2−3a+2b=−3⇒a=1∧b=0f(x)=xF(x)=∫xdx=x22+cF(2)=0⇒c=−2F(x)=x22−2F(−2)=0

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *