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f-x-4x-4-2x-2-17-Find-the-maximum-point-of-the-function-




Question Number 147980 by mathdanisur last updated on 24/Jul/21
f(x) = 4x^4  - 2x^2  + 17  Find the maximum point of the  function
f(x)=4x42x2+17Findthemaximumpointofthefunction
Answered by iloveisrael last updated on 25/Jul/21
f ′(x)=16x^3 −4x = 0  ⇒4x(4x^2 −1)=0  ⇒x=0 , x = ± (1/2)  f ′′(x)=48x^2 −4 < 0 for x = 0  local max when x = 0 , local max value = 17  local max point at (0,17)
f(x)=16x34x=04x(4x21)=0x=0,x=±12f(x)=48x24<0forx=0localmaxwhenx=0,localmaxvalue=17localmaxpointat(0,17)
Commented by mathdanisur last updated on 25/Jul/21
Thanks Ser
ThanksSer

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