Question Number 129527 by MathSh last updated on 16/Jan/21
$${f}\left({x}\right)=\begin{cases}{\mathrm{5}−{x}\:;\:{x}\geqslant\mathrm{2}}\\{{x}^{\mathrm{2}} +\mathrm{3}\:;\:{x}<\mathrm{2}}\end{cases}\:\:\:{if}, \\ $$$${find}:\:{f}\left(\mathrm{2}\right)+{f}\left(\mathrm{0}\right)=? \\ $$
Commented by bramlexs22 last updated on 16/Jan/21
$$=\:\mathrm{3}\:+\:\mathrm{3}\:=\:\mathrm{6} \\ $$