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f-x-ax-2-bx-c-f-x-1-f-x-f-x-1-x-2-1-f-2-




Question Number 192083 by sciencestudentW last updated on 07/May/23
f(x)=ax^2 +bx+c  f(x−1)+f(x)+f(x+1)=x^2 +1  f(2)=?
f(x)=ax2+bx+cf(x1)+f(x)+f(x+1)=x2+1f(2)=?
Answered by AST last updated on 07/May/23
Line 2  ⇒a((x−1)^2 +x^2 +(x+1)^2 )+b(x−1+x+x+1)+3c  =x^2 +1⇒a(3x^2 +2)+b(3x)+3c=x^2 +1  ⇒3ax^2 +3bx+2a+3c=x^2 +1  ⇒3a=1⇒a=(1/3);b=0;2a+3c=1⇒c=(1/9)  ⇒f(x)=(1/3)x^2 +(1/9)=((3x^2 +1)/9)  ⇒f(2)=((13)/9)
Line2a((x1)2+x2+(x+1)2)+b(x1+x+x+1)+3c=x2+1a(3x2+2)+b(3x)+3c=x2+13ax2+3bx+2a+3c=x2+13a=1a=13;b=0;2a+3c=1c=19f(x)=13x2+19=3x2+19f(2)=139

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