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f-x-ln-x-x-x-2-g-x-x-2-1-ln-x-Calculate-the-derivative-of-f-x-as-a-function-of-g-x-




Question Number 171546 by Kodjo last updated on 17/Jun/22
f(x)=((−ln∣x∣)/x)+x−2  ,   g(x)=−x^2 +1−ln∣x∣    Calculate the derivative of f(x) as a function of g(x)
f(x)=lnxx+x2,g(x)=x2+1lnxCalculate the derivative of f(x) as a function of g(x)
Commented by kaivan.ahmadi last updated on 17/Jun/22
f(x)=((−lnx+x^2 −2x)/x)=((g(x)+x^2 −1+x^2 −2x)/x)  =((g(x)−2x−1)/x)=((g(x))/x)−2−(1/x)  f′(x)=((xg′(x)−g(x))/x^2 )+(1/x^2 )=((xg′(x)−g(x)+1)/x^2 )
f(x)=lnx+x22xx=g(x)+x21+x22xx=g(x)2x1x=g(x)x21xf(x)=xg(x)g(x)x2+1x2=xg(x)g(x)+1x2

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