Question Number 157906 by HongKing last updated on 29/Oct/21
$$\mathrm{f}\left(\mathrm{x}\right)=\left(\mathrm{px}+\mathrm{1}\right)\left(\mathrm{2x}+\mathrm{q}+\mathrm{4}\right)\:\mathrm{function}\:\mathrm{is}\:\mathrm{a} \\ $$$$\mathrm{single}\:\mathrm{function},\:\mathrm{find}\:\boldsymbol{\mathrm{p}}+\boldsymbol{\mathrm{q}}+\boldsymbol{\mathrm{pq}}=? \\ $$$$ \\ $$
Commented by Rasheed.Sindhi last updated on 29/Oct/21
$${What}'{s}\:{meant}\:{by}\:'\mathrm{single}\:\mathrm{function}'? \\ $$
Commented by HongKing last updated on 29/Oct/21
$$\mathrm{sir},\:\mathrm{one}\:\mathrm{function}\: \\ $$
Commented by Rasheed.Sindhi last updated on 29/Oct/21
$$\mathrm{S}{e}\mathrm{r}\:\mathrm{excuse}\:\mathrm{me},\:\mathrm{have}\:\mathrm{you}\:\mathrm{lost}\:\mathrm{your} \\ $$$$\left.\mathrm{profile}\:\mathrm{again}?\::\right) \\ $$
Commented by HongKing last updated on 29/Oct/21
$$\left.\mathrm{sorry}\:\mathrm{sir}\:\mathrm{yes}\:\mathrm{l}\:\mathrm{lost}\:\mathrm{my}\:\mathrm{profile}\:\mathrm{again}\right) \\ $$