f-x-x-2-1-x-2-x-4-2x-2-1-f-3-

Question Number 174570 by blackmamba last updated on 04/Aug/22

{\begin{cases} f (\frac{x}{x^{2} + 1}) = \frac{x^{2}}{x^{4} + 2 x^{2} + 1} \\ f (\sqrt{3}) = ? \end{cases}

Commented by infinityaction last updated on 04/Aug/22

f (\frac{1}{x + \frac{1}{x}}) = \frac{1}{{(x + \frac{1}{x})}^{2}}

f (\sqrt{3}) = 3

Answered by Rasheed.Sindhi last updated on 05/Aug/22

f (\frac{x}{x^{2} + 1}) = \frac{x^{2}}{x^{4} + 2 x^{2} + 1}

f (\frac{x}{x^{2} + 1}) = {(\frac{x}{x^{2} + 1})}^{2}

R e p l a c i n g \frac{x}{x^{2} + 1} b y x

\begin{matrix} f (x) = x^{2} \end{matrix}

f (\sqrt{3}) = {(\sqrt{3})}^{2} = 3