Question Number 160630 by Brondon last updated on 03/Dec/21
$${f}\left({x}\right)={x}^{{x}^{{x}^{{x}^{{x}} } } } . \\ $$$${Df}\left({x}\right)=??? \\ $$$${svp}\:{les}\:{baos} \\ $$
Answered by stelor last updated on 03/Dec/21
$$\mathcal{R}−\left\{\mathrm{0}\right\}\:\:\:\:{according}\:{to}\:{me}. \\ $$
Answered by puissant last updated on 04/Dec/21
$${Df}\:=\:\mathbb{R}^{\ast} .. \\ $$
Commented by stelor last updated on 04/Dec/21
$${why}\:{only}\:{positives}\:{values}? \\ $$
Commented by puissant last updated on 04/Dec/21
$${On}\:{va}\:{prendre}\:{toute}\:{les}\:{valeurs}\:{de}\:\mathbb{R} \\ $$$${sauf}\:\mathrm{0} \\ $$