Figure-shows-an-arrangement-of-blocks-pulley-and-strings-Strings-and-pulley-are-massless-and-frictionless-The-relation-between-acceleration-of-the-blocks-as-shown-in-the-figure-is-

Question Number 21145 by Tinkutara last updated on 14/Sep/17

Figure shows an arrangement of blocks,

pulley and strings . Strings and pulley

are massless and frictionless . The

relation between acceleration of the

blocks as shown in the figure is

Commented by Tinkutara last updated on 14/Sep/17

Commented by mrW1 last updated on 14/Sep/17

T_{2} = m_{2} (g + a_{2})

m_{1} (g - a_{1}) = {6 T}_{2} = {6 m}_{2} (g + a_{2})

\frac{{6 m}_{2}}{m_{1}} (g + a_{2}) = g - a_{1}

\frac{{6 m}_{2}}{m_{1}} a_{2} + a_{1} = (1 - \frac{{6 m}_{2}}{m_{1}}) g

\Rightarrow {6 m}_{2} a_{2} + m_{1} a_{1} = (m_{1} - {6 m}_{2}) g

Commented by Tinkutara last updated on 15/Sep/17

How a_{2} = {6 a}_{1} ?

Commented by Tinkutara last updated on 14/Sep/17

Answer is a direct relation between

a_{1} and a_{2} .

Commented by mrW1 last updated on 15/Sep/17

a_{2} = {6 a}_{1}

\Rightarrow ({36 m}_{2} + m_{1}) a_{1} = (m_{1} - {6 m}_{2}) g

\Rightarrow a_{1} = \frac{m_{1} - {6 m}_{2}}{{36 m}_{2} + m_{1}} \times g

Commented by ajfour last updated on 15/Sep/17

f o r t h e l a r g e r b l o c k t o c o m e d o w n

b y x t h e s m a l l e r h a s t o r i s e b y 6 x .

s o x_{2} = 6 x_{1}

\Rightarrow v_{2} = 6 v_{1}

\Rightarrow a_{2} = 6 a_{1} .

Commented by Tinkutara last updated on 15/Sep/17

Thank you very much Sir!