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find-0-e-3x-log-2-1-e-2x-dx-

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Question Number 144221 by Mathspace last updated on 23/Jun/21
find ∫_0 ^∞ e^(−3x) log^2 (1+e^(2x) )dx
$${find}\:\int_{\mathrm{0}} ^{\infty} {e}^{−\mathrm{3}{x}} {log}^{\mathrm{2}} \left(\mathrm{1}+{e}^{\mathrm{2}{x}} \right){dx} \\ $$

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