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find-1-x-2-y-2-4-and-y-0-dxdy-x-2-y-2-




Question Number 31090 by abdo imad last updated on 02/Mar/18
find ∫∫_(1≤x^2  +y^2 ≤4 and y≥0)    ((dxdy)/( (√(x^2  +y^2 )))) .
find1x2+y24andy0dxdyx2+y2.
Commented by abdo imad last updated on 06/Mar/18
let use the polar coordinates x=rcosθ and y=rsinθ  due to diffeomorphisme we must have 1≤r≤2  and  0≤θ≤π ⇒ I= ∫_0 ^π  (∫_1 ^2  ((rdr)/( (√r^2 ))))dθ=∫_0 ^π  (∫_1 ^2 dr)dθ =∫_0 ^π dθ=π .
letusethepolarcoordinatesx=rcosθandy=rsinθduetodiffeomorphismewemusthave1r2and0θπI=0π(12rdrr2)dθ=0π(12dr)dθ=0πdθ=π.

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