Find-2003-2005-3-2004-2002-3-

Question Number 183363 by Shrinava last updated on 25/Dec/22

Find :

2003 \cdot 2005^{3} - 2004 \cdot 2002^{3}

Answered by Frix last updated on 25/Dec/22

(x - \frac{1}{2}) {(x + \frac{3}{2})}^{3} - (x + \frac{1}{2}) {(x - \frac{3}{2})}^{3} = 8 x^{3}

\Rightarrow

answer is 8 \times \frac{4007^{3}}{2^{3}} = 4007^{3}

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