Find-a-point-on-the-curve-y-x-where-the-tangent-makes-an-angle-45-with-the-positive-x-axis-

Question Number 147713 by Odhiambojr last updated on 22/Jul/21

F i n d a p o i n t o n t h e c u r v e y = \sqrt{x}

w h e r e t h e t a n g e n t m a k e s a n a n g l e

45 ° w i t h t h e p o s i t i v e x - a x i s

Answered by Olaf_Thorendsen last updated on 22/Jul/21

\frac{d y}{d x} = \tan (θ (x)) = \frac{1}{2 \sqrt{x}}

If θ (x) = 45 °, \frac{1}{2 \sqrt{x}} = 1 \Rightarrow x = \frac{1}{4}

Commented by Odhiambojr last updated on 22/Jul/21

t h a k s M r .