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Question Number 115906 by Eric002 last updated on 29/Sep/20
find all pairs of integers (x,y) such that  x^3 +y^3 =(x+y)^2
findallpairsofintegers(x,y)suchthatx3+y3=(x+y)2
Answered by mindispower last updated on 29/Sep/20
x^3 +y^3 =(x+y)(x^2 +y^2 −xy)  ⇔(x+y)(x^2 +y^2 −xy−(x+y))=0  x=−y  or  x^2 +y^2 −xy−(x+y)=0  y^2 +y(−1−x)+x^2 −x=0  Δ=x^2 +2x+1−4x^2 +4x≥0  ⇒6x−4x^2 +1≥0  x∈[((−6+(√(48)))/(−8)),((6+(√(48)))/8)]   0≤x≤1  x=0⇒y^2 −y=0⇒y∈{0,1}  x=1⇒y^2 −2y=0  y∈{0,2}  S={(a,−a);(0,1);(0,2)}
x3+y3=(x+y)(x2+y2xy)(x+y)(x2+y2xy(x+y))=0x=yorx2+y2xy(x+y)=0y2+y(1x)+x2x=0Δ=x2+2x+14x2+4x06x4x2+10x[6+488,6+488]0x1x=0y2y=0y{0,1}x=1y22y=0y{0,2}S={(a,a);(0,1);(0,2)}

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