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Find-all-solution-7cos-3x-1-3-for-x-over-the-interval-0-2pi-




Question Number 126005 by bramlexs22 last updated on 16/Dec/20
  Find all solution 7cos (3x)−1= 3   for x over the interval [ 0,2π ]
Findallsolution7cos(3x)1=3forxovertheinterval[0,2π]
Commented by liberty last updated on 16/Dec/20
 7 cos (3x)=4 ⇒cos (3x)=(4/7)    3x = cos^(−1) ((4/7)) = 0.963   3x =  { ((0.963+k.2π)),((−0.963+k.2π)) :} ⇔ x= { ((0.321+((2kπ)/3))),((−0.321+((2kπ)/3))) :}
7cos(3x)=4cos(3x)=473x=cos1(47)=0.9633x={0.963+k.2π0.963+k.2πx={0.321+2kπ30.321+2kπ3

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