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Question Number 180856 by Shrinava last updated on 18/Nov/22
find all values of  m∈R  such that the equation:                         ∫_0 ^( x)  ((arctany)/y) dy = mx  has two real roots:   x_1 ∈(−∞;0) , x_2 ∈(0;∞)
findallvaluesofmRsuchthattheequation:0xarctanyydy=mxhastworealroots:x1(;0),x2(0;)
Answered by mr W last updated on 19/Nov/22
f(x)=∫_0 ^x ((tan^(−1) t)/t)dt  g(x)=mx  we can see f(x) is an odd function,  i.e. f(−x)=−f(x).  f′(x)=((tan^(−1) x)/x)  f′(0)=lim_(x→0) ((tan^(−1) x)/x)=1  i.e. the tangent of y=f(x) at x=0 is   y=kx with k=1.  lim_(x→+∞) f′(x)=lim_(x→+∞) ((tan^(−1) x)/x)=0  so we can know how the graph of  y=f(x) nearly looks like. the line   y=mx always intersects the curve   y=f(x) at x=0 and additionally at   two points P and P′ with x=±a  if y=mx is flater than the tangent  line at x=0, i.e. if 0<m<k=1.  that means if 0<m<1, the eqn.  f(x)=g(x) will have two roots:  x=±a. so the answer is 0<m<1.
f(x)=0xtan1ttdtg(x)=mxwecanseef(x)isanoddfunction,i.e.f(x)=f(x).f(x)=tan1xxf(0)=limx0tan1xx=1i.e.thetangentofy=f(x)atx=0isy=kxwithk=1.limx+f(x)=limx+tan1xx=0sowecanknowhowthegraphofy=f(x)nearlylookslike.theliney=mxalwaysintersectsthecurvey=f(x)atx=0andadditionallyattwopointsPandPwithx=±aify=mxisflaterthanthetangentlineatx=0,i.e.if0<m<k=1.thatmeansif0<m<1,theeqn.f(x)=g(x)willhavetworoots:x=±a.sotheansweris0<m<1.
Commented by mr W last updated on 19/Nov/22
Commented by mr W last updated on 19/Nov/22
for the solition of the question, we  don′t need to solve the integral  ∫_0 ^x  ((tan^(−1) t)/t)dt really. to be honest, i can′t  solve it. but it′s enough to know how  its graph nearly looks like.
forthesolitionofthequestion,wedontneedtosolvetheintegral0xtan1ttdtreally.tobehonest,icantsolveit.butitsenoughtoknowhowitsgraphnearlylookslike.
Commented by Shrinava last updated on 19/Nov/22
perfect dear professor thank you
perfectdearprofessorthankyou

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