Find-an-orthogonal-matrix-A-whose-first-row-is-u-1-1-3-2-3-2-3- Tinku Tara June 4, 2023 Matrices and Determinants 0 Comments FacebookTweetPin Question Number 116746 by bemath last updated on 06/Oct/20 FindanorthogonalmatrixAwhosefirstrowisu1=(13,23,23). Answered by john santu last updated on 06/Oct/20 Firststepfindanonzerovectorw1=(x,y,z)thatisorthogonaltou1.forwhich⟨u1,w1⟩=0=x3+2y3+2z3orx+2y+2z=0.Onesuchsolutionisw1=(0,1,−1).Normalizew1toobtainthesecondrowofA,u2=(0,12,−12)Nextstepfindanonzerovectorw2=(x,y,z)thatisorthogonaltobothu1andu2forwhich⟨u1,w2⟩=0and⟨u2,w2⟩=0⇒⟨u1,w2⟩=x3+2y3+2z3=0⇒⟨u2,w2⟩=y2−z2=0setz=−1andfindthesolutionw2=(4,−1,−1).Normalizew2andobtainthethirdrowofA,thatisu3=(418,−118,−118)ThusA=(132323012−12418−118−118)WeemphasizethattheabovematrixAisnotunique. Commented by bemath last updated on 06/Oct/20 waw…thanksalotmrfarmermath Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: nice-calculus-prove-that-1-e-4x-x-1-dx-pi-2-e-4-m-n-1970-Next Next post: 1-lim-x-i-2-z-i-2-2z-i-3-z-2-lim-x-e-pii-4-2z-2-z-3-z-1-3-lim-x-2i-2z-2-8-z-4-3-64-4-lim-x-0-cos-4z-1-z-sin-z- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.