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find-arg-z-given-that-z-1-i-1-i-




Question Number 84564 by Rio Michael last updated on 14/Mar/20
find arg(z) given that  z = ((1 + i)/(1−i))
findarg(z)giventhatz=1+i1i
Commented by mr W last updated on 14/Mar/20
z=((1+i)/(1−i))=(((1+i)(1+i))/(1−i^2 ))=((1+2i+i^2 )/2)=i  =cos ((π/2))+i sin ((π/2))  ⇒arg(z)=(π/2)
z=1+i1i=(1+i)(1+i)1i2=1+2i+i22=i=cos(π2)+isin(π2)arg(z)=π2

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