find-arg-z-where-z-1-cos-icos-

Question Number 127605 by pticantor last updated on 31/Dec/20

f i n d a r g (z)

w h e r e z = 1 + c o s α + i c o s β

Answered by MJS_new last updated on 31/Dec/20

\arg (1 + \cos α + i \cos β) =

= \frac{π}{2} sign (\cos β) - \arctan \frac{1 + \cos α}{\cos β}

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