find-ax-x-2-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 101531 by mhmd last updated on 03/Jul/20 find∫ax−x2dx Answered by Mr.D.N. last updated on 03/Jul/20 I=∫ax−x2dx=∫−(x2−ax)dx=∫(a2)2−(x−a2)2dx=(x−a2)(a2)2−(x−a2)22+(a2)22sin−1(x−a2)a2+C=2x−a2ax−x22+a28sin−12x−aa+C=(2x−a)ax−x24+a28sin−1(2x−a)a+C//. Commented by mhmd last updated on 03/Jul/20 thankyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: ln-sinx-dx-Next Next post: Let-the-triangle-A-3-2-B-8-4-C-4-6-solve-a-find-the-perimeter-b-find-the-area-c-find-the-base-d-find-the-height-e-classify-it- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.