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Question Number 96383 by bobhans last updated on 01/Jun/20
Find domain & range of function   f(x) = (1/(x^2 −5x+6))
Finddomain&rangeoffunctionf(x)=1x25x+6
Answered by john santu last updated on 01/Jun/20
The domain consists of all real   number except 2 and 3. To determine  the range , set y = (1/(x^2 −5x+6))   and solve for x. ⇒x^2 −5x+(6−(1/y)) =0  This has solution when and only  when b^2 −4ac = 25−24+(4/y)≥0  This holds if only if (4/y)≥−1   this holds when y > 0 , and if  y<0 , when y ≤ −4. Hence the   range is (−∞,−4 ] ∪ (0, ∞ )
Thedomainconsistsofallrealnumberexcept2and3.Todeterminetherange,sety=1x25x+6andsolveforx.x25x+(61y)=0Thishassolutionwhenandonlywhenb24ac=2524+4y0Thisholdsifonlyif4y1thisholdswheny>0,andify<0,wheny4.Hencetherangeis(,4](0,)
Commented by bemath last updated on 01/Jun/20
thank you for the explanation

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