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find-dx-4x-x-2-




Question Number 33329 by prof Abdo imad last updated on 14/Apr/18
find  ∫   (dx/( (√(4x−x^2 )))) .
finddx4xx2.
Commented by prof Abdo imad last updated on 19/Apr/18
I  = ∫     (dx/( (√(−x^2  +4x)))) = ∫   (dx/( (√(−(x^2 −4x +4) +4))))  =∫     (dx/( (√(4 −(x−2)^2 ))))  .changement x−2= 2sinθ  =∫        ((2 cosθ dθ)/( (√(4−4sin^2 θ)))) = ∫ dθ =θ  +c  = arcsin((x/2)−1) +c .
I=dxx2+4x=dx(x24x+4)+4=dx4(x2)2.changementx2=2sinθ=2cosθdθ44sin2θ=dθ=θ+c=arcsin(x21)+c.

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