find-dx-4x-x-2- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 33329 by prof Abdo imad last updated on 14/Apr/18 find∫dx4x−x2. Commented by prof Abdo imad last updated on 19/Apr/18 I=∫dx−x2+4x=∫dx−(x2−4x+4)+4=∫dx4−(x−2)2.changementx−2=2sinθ=∫2cosθdθ4−4sin2θ=∫dθ=θ+c=arcsin(x2−1)+c. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: find-0-1-dx-3-e-x-Next Next post: Question-33330 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.