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find-dx-tan-1-x-




Question Number 96092 by mhmd last updated on 29/May/20
find ∫(dx/(tan^(−1) (x)))
finddxtan1(x)
Commented by bemath last updated on 30/May/20
∫ cot^(−1) (x) dx = I  by parts . u = cot^(−1) (x)⇒du=−(√(1−x^2 )) dx  dv = dx ⇒ v = x  I = x cot^(−1) (x)+ ∫ x(√(1−x^2 )) dx   I = x cot^(−1) (x)−(1/2)∫ (√(1−x^2 )) d(1−x^2 )  I = x cot^(−1) (x)−(1/3)(√((1−x^2 )^3 )) + c
cot1(x)dx=Ibyparts.u=cot1(x)du=1x2dxdv=dxv=xI=xcot1(x)+x1x2dxI=xcot1(x)121x2d(1x2)I=xcot1(x)13(1x2)3+c
Commented by Kunal12588 last updated on 30/May/20
(1/(tan^(−1) x)) ≠ cot^(−1) x  [tan^(−1) ((1/x))=cot^(−1) x]
1tan1xcot1x[tan1(1x)=cot1x]
Commented by mathmax by abdo last updated on 30/May/20
answer not correct!
answernotcorrect!
Commented by MJS last updated on 30/May/20
this cannot be solved
thiscannotbesolved

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