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find-dx-x-2-x-2-x-2-x-2-




Question Number 144216 by Mathspace last updated on 23/Jun/21
find ∫   (dx/( (√(x^2 +x+2))+(√(x^2 −x+2))))
finddxx2+x+2+x2x+2
Answered by bemath last updated on 23/Jun/21
(1/( (√(x^2 +x+2))+(√(x^2 −x+2)))) = (((√(x^2 +x+2))−(√(x^2 −x+2)))/(2x))  I=∫ ((√(x^2 +x+2))/(2x)) dx−∫ ((√(x^2 −x+2))/(2x)) dx
1x2+x+2+x2x+2=x2+x+2x2x+22xI=x2+x+22xdxx2x+22xdx

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