Question Number 28280 by Cheyboy last updated on 23/Jan/18

Commented by abdo imad last updated on 23/Jan/18

Commented by Cheyboy last updated on 23/Jan/18

Commented by abdo imad last updated on 23/Jan/18

Commented by Cheyboy last updated on 24/Jan/18

Answered by ajfour last updated on 24/Jan/18
![y=x^(2/3) (6−x)^(1/3) ln y=(2/3)ln x+(1/3)ln (6−x) (1/y)(dy/dx)=(2/(3x))−(1/(3(6−x))) (dy/dx)=y[((12−2x−x)/(3x(6−x)))] (dy/dx)=((x^(2/3) (6−x)^(1/3) (4−x))/(x(6−x))) =((4−x)/(x^(1/3) (6−x)^(2/3) )) .](https://www.tinkutara.com/question/Q28333.png)
Commented by Cheyboy last updated on 24/Jan/18

Commented by Cheyboy last updated on 24/Jan/18

Commented by abdo imad last updated on 24/Jan/18
