find-f-a-dx-1-ax-2-1-ax-2-with-a-gt-0- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 51991 by maxmathsup by imad last updated on 01/Jan/19 findf(a)=∫dx1+ax2+1−ax2witha>0 Commented by Abdo msup. last updated on 05/Jan/19 changementxa=tgivef(a)=∫dta(1+t2+1−t2)=1a∫dt1+t2+1−t2⇒af(a)=∫1+t2−1−t22t2dt=12∫1+t2t2dt−12∫1−t2t2dtbutbyparts∫1+t2t2dt=−1+t2t−∫−1t2t21+t2dt=−1+t2t+ln(t+1+t2)+c1alsobypsrts∫1−t2t2dt=−1−t2t−∫−1t−2t21−t2dt=−1−t2t−arcsint+c2⇒f(a)=12a{−1+t2t+ln(t+1+t2)+1−t2t+arcsint}+C. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-1-xsec-2x-dx-Next Next post: find-A-n-x-0-1-1-t-2-n-cos-tx-dt- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.