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Find-GP-the-matrix-permutation-where-P-a-b-c-d-b-c-a-d-and-G-a-b-c-d-a-c-d-b-explain-




Question Number 125262 by physicstutes last updated on 09/Dec/20
Find GP the matrix permutation where   P =  ((a,b,c,d),(b,c,a,d) ) and G =  ((a,b,c,d),(a,c,d,b) )  explain
$$\mathrm{Find}\:{GP}\:\mathrm{the}\:\mathrm{matrix}\:\mathrm{permutation}\:\mathrm{where} \\ $$$$\:{P}\:=\:\begin{pmatrix}{{a}}&{{b}}&{{c}}&{{d}}\\{{b}}&{{c}}&{{a}}&{{d}}\end{pmatrix}\:\mathrm{and}\:{G}\:=\:\begin{pmatrix}{{a}}&{{b}}&{{c}}&{{d}}\\{{a}}&{{c}}&{{d}}&{{b}}\end{pmatrix} \\ $$$$\mathrm{explain} \\ $$
Commented by kaivan.ahmadi last updated on 09/Dec/20
GP= (((a      b       c      d)),((c       d       a     b)) )
$${GP}=\begin{pmatrix}{{a}\:\:\:\:\:\:{b}\:\:\:\:\:\:\:{c}\:\:\:\:\:\:{d}}\\{{c}\:\:\:\:\:\:\:{d}\:\:\:\:\:\:\:{a}\:\:\:\:\:{b}}\end{pmatrix} \\ $$

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