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Question Number 33425 by Rio Mike last updated on 16/Apr/18
find k if the deteminant of       (((3         k)),((2          3)) )   is 2   can someone please teach me how  to find the deteminant of a 3×3  matrix ?
findkifthedeteminantof(3k23)is2cansomeonepleaseteachmehowtofindthedeteminantofa3×3matrix?
Commented by Joel578 last updated on 16/Apr/18
9 − 2k = 2  k = (7/2)
92k=2k=72
Commented by Joel578 last updated on 16/Apr/18
For 3×3 matrice, you can learn from youtube or  textbooks
For3×3matrice,youcanlearnfromyoutubeortextbooks
Commented by prof Abdo imad last updated on 17/Apr/18
if A = (((a    b     c)),((e     f     g)) )                   (k    l      m  det A =a ∣_(l         m) ^(f       g) ∣ −e∣_(l       m) ^(b      c) ∣ +k  ∣_(f      g) ^(b     c) ∣  =a( fm−lg) −e(bm−lc) +k(bg −fc) let take  example  A =  (((1     −1      o)),((2          1       3)) )             (−1      2        4 )  det A = 1∣_(2       4) ^(1       3) ∣ −2∣_(2            4) ^(−1      0) ∣ +(−1)∣_(1             3) ^(−1      0) ∣  =4−6  −2(−4) −1(−3)  =−2 +8 +3 = 9 .
ifA=(abcefg)(klmdetA=almfgelmbc+kfgbc=a(fmlg)e(bmlc)+k(bgfc)lettakeexampleA=(11o213)(124)detA=1241322410+(1)1310=462(4)1(3)=2+8+3=9.
Answered by MJS last updated on 16/Apr/18
det ((a,b),(c,d) )=ad−bc  det ((a,b,c),(d,e,f),(g,h,i) )=_(−(afh+bdi+ceg)) ^((aei+bfg+cdh)−)
det(abcd)=adbcdet(abcdefghi)=(afh+bdi+ceg)(aei+bfg+cdh)

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