Question Number 160658 by HongKing last updated on 04/Dec/21
![Find: lim_(x→0) 4x [ (1/(4x)) ] = ?](https://www.tinkutara.com/question/Q160658.png)
Commented by mr W last updated on 04/Dec/21
![lim_(x→0) 4x[(1/(4x))] =lim_(t→∞) (([t])/t)=L t−1<[t]≤t lim_(t→∞) ((t−1)/t)<L≤lim_(t→∞) (t/t) 1<L≤1 ⇒L=1](https://www.tinkutara.com/question/Q160663.png)
Commented by mnjuly1970 last updated on 04/Dec/21

Commented by HongKing last updated on 04/Dec/21

Answered by mathmax by abdo last updated on 04/Dec/21
![we have [(1/(4x))]≤(1/(4x))<[(1/(4x))]+1 ⇒(1/(4x))−1<[(1/(4x))]≤(1/(4x)) ⇒ for x>0 we have 1−4x<4x.[(1/(4x))]≤1 ⇒ lim_(x→0^+ ) 4x[(1/(4x))]=1](https://www.tinkutara.com/question/Q160686.png)
Commented by HongKing last updated on 04/Dec/21
