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find-lim-x-0-ln-sin-xcos-1-x-1-if-it-exits-




Question Number 85057 by kushdasbaghar@gmail.com last updated on 18/Mar/20
find lim_(x→0) ln (sin xcos (1/x)+1) if it exits.
findlimlnx0(sinxcos1x+1)ifitexits.
Commented by abdomathmax last updated on 19/Mar/20
we have ln(1+sinx cos((1/x)))∼sinx cos((1/x)) (x→0)  sinx cos((1/x))∼xcos((1/x)) and ∣xcos((1/x))∣≤∣x∣→0 ⇒  lim_(x→0) sinx cos((1/x))=0 ⇒lim_(x→0)  ln(sinxcos((1/x))+1)=0
wehaveln(1+sinxcos(1x))sinxcos(1x)(x0)sinxcos(1x)xcos(1x)andxcos(1x)∣⩽∣x∣→0limx0sinxcos(1x)=0limx0ln(sinxcos(1x)+1)=0

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