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find-lim-x-0-sin-shx-sh-sinx-x-




Question Number 35727 by abdo mathsup 649 cc last updated on 22/May/18
find lim_(x→0)      ((sin(shx) −sh(sinx))/x)
findlimx0sin(shx)sh(sinx)x
Commented by abdo mathsup 649 cc last updated on 23/May/18
its beter to use hospital theorem in this case  let put f(x)=sin(shx) −sh(sinx) and  g(x)=x we have  f^′ (x) = ch(x)cos(shx) −cos(x) ch(sinx) ⇒  lim_(x→0)  f(x) = 1 −1 =0  g^′ (x) =1  so  lim_(x→0)  ((sin(shx) −sh(sinx))/x) =0
itsbetertousehospitaltheoreminthiscaseletputf(x)=sin(shx)sh(sinx)andg(x)=xwehavef(x)=ch(x)cos(shx)cos(x)ch(sinx)limx0f(x)=11=0g(x)=1solimx0sin(shx)sh(sinx)x=0

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