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Find-lim-x-2-2-sin-4x-1-cos-4x-Find-lim-x-2-sin-6x-1-cos-6x-




Question Number 189757 by Shrinava last updated on 21/Mar/23
Find:     lim_(x→(𝛑/2))  (((√2) ∣ sin 4x ∣)/( (√(1 − cos 4x))))   =   ?  Find:     lim_(x→𝛑)  (((√2) ∣ sin 6x ∣)/( (√(1 − cos 6x))))   =   ?
Find:limxπ22sin4x1cos4x=?Find:limxπ2sin6x1cos6x=?
Answered by Frix last updated on 21/Mar/23
Use t=tan 2x in the 1^(st)  and t=tan 3x in the  2^(nd)  with t→0 ⇒ answer is 2
Uset=tan2xinthe1standt=tan3xinthe2ndwitht0answeris2
Answered by mehdee42 last updated on 21/Mar/23
1)lim_(x→(π/2)) ((2(√2)∣sin2xcos2x∣)/( (√2)∣sin2x∣))=lim_(x→(π/2)) 2∣cos2x∣=2  2)lim_(x→π) ((2(√2)∣sin3xcos3x∣)/( (√2)∣sin3x∣))=lim_(x→π) 2∣cos3x∣=2
1)limxπ222sin2xcos2x2sin2x=limxπ22cos2x∣=22)limxπ22sin3xcos3x2sin3x=limxπ2cos3x∣=2
Commented by Shrinava last updated on 24/Mar/23
thank you professor
thankyouprofessor

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