find-lim-x-3-x-3-27-x-5-243-

Question Number 79064 by Khyati last updated on 22/Jan/20

f i n d l i \underset{x \to - 3}{m} \frac{x^{3} + 27}{x^{5} + 243}

Answered by john santu last updated on 22/Jan/20

\lim_{x \to - 3} \frac{\frac{d}{d x} (x^{3} + 27)}{\frac{d}{d x} (x^{5} + 243)} = \lim_{x \to - 3} \frac{3 x^{2}}{5 x^{4}} = \frac{3}{5 \times 9}

\frac{1}{15}

Commented by Khyati last updated on 23/Jan/20

s o l v e w i t h o u t L H o s p i t a l r u l e

Commented by john santu last updated on 23/Jan/20

u s i n g H o r n e r m e t h o d s i r

Commented by john santu last updated on 23/Jan/20

\lim_{x \to - 3} \frac{(x + 3) (x^{2} - 3 x + 9)}{(x + 3) (x^{4} - 3 x^{3} + 9 x^{2} - 27 x + 81)}

\lim_{x \to - 3} \frac{x^{2} - 3 x + 9}{x^{4} - 3 x^{3} + 9 x^{2} - 27 x + 81}

Commented by Khyati last updated on 23/Jan/20

H o r n e r M e t h o d ? ? ? ? ?

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