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Question Number 153105 by alisiao last updated on 04/Sep/21
find  ln 𝚪(x) ?
findlnΓ(x)?
Answered by puissant last updated on 04/Sep/21
ln(Γ(x))=−γx−lnx+Σ_(k=1) ^∞ {(x/k)−ln(1+(x/k))}  =(x−(1/2))lnx−x+(1/2)ln(2π)+(1/2)Σ_(n=2) ^∞ (((n−1))/(n(n+1)))ζ(n,x+1)  =(x−(1/2))lnx−x+(1/2)ln(2π)+2∫_0 ^∞ ((arctan((x/a)))/(e^(2πx) −1))dx.
ln(Γ(x))=γxlnx+k=1{xkln(1+xk)}=(x12)lnxx+12ln(2π)+12n=2(n1)n(n+1)ζ(n,x+1)=(x12)lnxx+12ln(2π)+20arctan(xa)e2πx1dx.

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