find-ln-x- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 153105 by alisiao last updated on 04/Sep/21 findlnΓ(x)? Answered by puissant last updated on 04/Sep/21 ln(Γ(x))=−γx−lnx+∑∞k=1{xk−ln(1+xk)}=(x−12)lnx−x+12ln(2π)+12∑∞n=2(n−1)n(n+1)ζ(n,x+1)=(x−12)lnx−x+12ln(2π)+2∫0∞arctan(xa)e2πx−1dx. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-pi-x-3-x-3-pi-x-3-dx-Next Next post: 0-1-3x-2-2x-1-dx-as-the-limit-of-sum- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.