Find-m-n-p-1-p-2-m-2n-p-1-1-log-p-1-p-2-n-p-2-1-log-p-1-p-2-n-

Tinku Tara June 4, 2023 Algebra 0 Comments

Question Number 130242 by Raxreedoroid last updated on 23/Jan/21

Find m n=(p_1 p_2 )^m 2n=(p_1 ^(1+log_(p_1 p_2 ) n) )(p_2 ^(1+log_(p_1 p_2 ) n) )

$$\mathrm{Find}\:\:\:{m} \\ $$$${n}=\left({p}_{\mathrm{1}} {p}_{\mathrm{2}} \right)^{{m}} \\ $$$$\mathrm{2}{n}=\left({p}_{\mathrm{1}} ^{\mathrm{1}+{log}_{{p}_{\mathrm{1}} {p}_{\mathrm{2}} } {n}} \right)\left({p}_{\mathrm{2}} ^{\mathrm{1}+{log}_{{p}_{\mathrm{1}} {p}_{\mathrm{2}} } {n}} \right) \\ $$

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