Find-minimum-value-of-y-1-sin-2-x-2-tan-2-x-

Question Number 192343 by cortano12 last updated on 15/May/23

Find minimum value of

y = \frac{1 - \sin^{2} x}{2 \tan^{2} x}

Answered by manxsol last updated on 15/May/23

x \neq k π \frac{π}{2} y > 0

2 {y s i n}^{2} x = {(1 - {s i n}^{2} x)}^{2}

{s i n}^{4} x - (2 + 2 y) {s i n}^{2} x + 1

Δ > 0

{(2 + 2 y)}^{2} - 4 > 0

y < - 2 \cap y > 0

s o l y > 0 - {f (x) / x = k π / 2}

m i n y > 0

Commented by mehdee42 last updated on 15/May/23

o k

t h e r e i s n o t m i n i m u m