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Question Number 85248 by jagoll last updated on 20/Mar/20
find minimum y = 2∣x−3∣ + ∣4x+2∣
findminimumy=2∣x−3∣+∣4x+2∣
Commented by mr W last updated on 20/Mar/20
x−3=0 ⇒x=3 4x+2=0 ⇒x=−(1/2) f(3)=∣12+2∣=14 f(−(1/2))=2∣−(1/2)−3∣=7 y_(min) =min(f(3),f(−(1/2)))=7
x−3=0⇒x=34x+2=0⇒x=−12f(3)=∣12+2∣=14f(−12)=2∣−12−3∣=7ymin=min(f(3),f(−12))=7

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