Question Number 44526 by arnabmaiti550@gmail.com last updated on 30/Sep/18

Commented by tanmay.chaudhury50@gmail.com last updated on 01/Oct/18

Answered by ajfour last updated on 30/Sep/18
![I =∫_0 ^( 2π) [∫_0 ^( r) ρr^2 (rdr)]dθ = (ρ/4)∫_0 ^( 2π) a^4 cos^2 2θ dθ = ((ρa^4 )/8)∫_0 ^( 2π) (1+cos 4θ)dθ = ((𝛒a^4 𝛑)/4) .](https://www.tinkutara.com/question/Q44530.png)
Commented by arnabmaiti550@gmail.com last updated on 01/Oct/18

Commented by ajfour last updated on 01/Oct/18

Commented by arnabmaiti550@gmail.com last updated on 01/Oct/18
