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Find-n-if-133-5-110-5-84-5-27-5-n-5-




Question Number 155174 by Fridunatjan08 last updated on 26/Sep/21
Find n if:  133^5 +110^5 +84^5 +27^5 =n^5
$${Find}\:{n}\:{if}: \\ $$$$\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} ={n}^{\mathrm{5}} \\ $$
Answered by MJS_new last updated on 26/Sep/21
144
$$\mathrm{144} \\ $$
Commented by Fridunatjan08 last updated on 02/Oct/21
please sir show me the steps.
$${please}\:{sir}\:{show}\:{me}\:{the}\:{steps}. \\ $$
Answered by Skabetix last updated on 26/Sep/21
(133^5 +110^5 +84^5 +27^5 )^((1/5)) =n=144
$$\left(\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} \right)^{\left(\mathrm{1}/\mathrm{5}\right)} ={n}=\mathrm{144} \\ $$

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