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Find-n-in-this-equation-2-n-4096-




Question Number 106630 by zahaku last updated on 06/Aug/20
Find n in this equation:  (−2)^n  = 4096
Findninthisequation:(2)n=4096
Answered by bemath last updated on 06/Aug/20
(−2)^n =(1024)×4=(2)^(12) =(−2)^(12)   →n = 12 . @bemath@
(2)n=(1024)×4=(2)12=(2)12n=12.@bemath@
Commented by zahaku last updated on 06/Aug/20
There isn′t another way to find n  in the same equation ?
Thereisntanotherwaytofindninthesameequation?
Answered by Aziztisffola last updated on 06/Aug/20
 n is even ⇒n=2p   (−2)^n  = 4096⇔ (−2)^(2p) =4096   ⇔4^p =4096 ⇒ln(4^p )=ln(4096)  ln(4)p=ln(4096) ⇒p=((ln(4096))/(2ln(2)))   2p=((ln(4096))/(ln(2)))=12   2p=12=n ⇒n=12.
nisevenn=2p(2)n=4096(2)2p=40964p=4096ln(4p)=ln(4096)ln(4)p=ln(4096)p=ln(4096)2ln(2)2p=ln(4096)ln(2)=122p=12=nn=12.
Commented by zahaku last updated on 06/Aug/20
Please can you explain how (−2)^(2p)  becomes 4p ?
Pleasecanyouexplainhow(2)2pbecomes4p?
Commented by Aziztisffola last updated on 06/Aug/20
(−2)^(2p) =((−2)^2 )^p =4^p
(2)2p=((2)2)p=4p
Commented by zahaku last updated on 06/Aug/20
Thank you.
Thankyou.
Commented by Aziztisffola last updated on 06/Aug/20
you′re welcome
yourewelcome

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