find-pi-6-pi-3-dx-cos-x-sin-x- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 34282 by math khazana by abdo last updated on 03/May/18 find∫π6π3dxcos(x)sin(x) Commented by math khazana by abdo last updated on 07/May/18 I=∫π6π32dxsin(2x)=2∫π6π3dxsin(2x)=2[12ln∣tanx∣]π6π3=ln(tan(π3))−ln(tan(π6))=ln(3)−ln(13)=2ln(3)=ln(3). Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: calculate-1-3-x-1-x-2-x-2-1-dx-Next Next post: sove-sinx-y-cos-2x-y-xe-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.