Question Number 114272 by bemath last updated on 18/Sep/20

Commented by malwaan last updated on 18/Sep/20

Commented by bemath last updated on 18/Sep/20

Commented by abdullahquwatan last updated on 18/Sep/20

Answered by bemath last updated on 18/Sep/20

Answered by malwaan last updated on 18/Sep/20

Answered by Dwaipayan Shikari last updated on 18/Sep/20
![cos3x+cosx=0 2cos2xcosx=0 cos2x=0 2x=kπ+(π/2) x=((kπ)/2)+(π/4) or x=kπ+(π/2) (k∈Z) Solution set x∈[(π/4),((3π)/4),((5π)/4),((7π)/4),((9π)/4),((11π)/4)] x∈[(π/2),((3π)/2),((5π)/2)]](https://www.tinkutara.com/question/Q114278.png)