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Question Number 101057 by bemath last updated on 30/Jun/20
Find the area bounded the   curves f(x)= ∣x^3 −4x^2 +3x∣ and   x−axis
Findtheareaboundedthecurvesf(x)=x34x2+3xandxaxis
Answered by john santu last updated on 30/Jun/20
Commented by john santu last updated on 30/Jun/20
Area = ∫_0 ^1 (x^3 −4x^2 +3x) dx −∫_1 ^3 (x^3 −4x^2 +3x)dx  = [(1/4)x^4 −(4/3)x^3 +(3/2)x^2  ]_0 ^1 −  [ (1/4)x^4 −(4/3)x^3 +(3/2)x^2 ]_1 ^3    = (5/(12))−((1/4)(80)−(4/3)(26)+(3/2)(8))  = (5/(12))+((104)/3)−32 = (5/(12)) + (8/3)  = ((37)/(12))★
Area=10(x34x2+3x)dx31(x34x2+3x)dx=[14x443x3+32x2]01[14x443x3+32x2]13=512(14(80)43(26)+32(8))=512+104332=512+83=3712
Commented by bemath last updated on 30/Jun/20
thank
thank

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