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Question Number 171006 by Mastermind last updated on 06/Jun/22
Find the area enclosed by the curve  y=4−3x^2  and the x−axis between  x_1 =−1 and x_2 =1.    Mastermind
Findtheareaenclosedbythecurvey=43x2andthexaxisbetweenx1=1andx2=1.Mastermind
Commented by kaivan.ahmadi last updated on 09/Jun/22
∫_(−1) ^1 (4−3x^2 )dx=(4x−x^3 )∣_(−1) ^1 =4−1+4−1=6
11(43x2)dx=(4xx3)11=41+41=6

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