Question Number 171006 by Mastermind last updated on 06/Jun/22
$${Find}\:{the}\:{area}\:{enclosed}\:{by}\:{the}\:{curve} \\ $$$${y}=\mathrm{4}−\mathrm{3}{x}^{\mathrm{2}} \:{and}\:{the}\:{x}−{axis}\:{between} \\ $$$${x}_{\mathrm{1}} =−\mathrm{1}\:{and}\:{x}_{\mathrm{2}} =\mathrm{1}. \\ $$$$ \\ $$$${Mastermind} \\ $$
Commented by kaivan.ahmadi last updated on 09/Jun/22
$$\int_{−\mathrm{1}} ^{\mathrm{1}} \left(\mathrm{4}−\mathrm{3}{x}^{\mathrm{2}} \right){dx}=\left(\mathrm{4}{x}−{x}^{\mathrm{3}} \right)\mid_{−\mathrm{1}} ^{\mathrm{1}} =\mathrm{4}−\mathrm{1}+\mathrm{4}−\mathrm{1}=\mathrm{6} \\ $$