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Question Number 116520 by kaivan.ahmadi last updated on 04/Oct/20

f i n d t h e c e n t e r o f c i r c l e w i t h r a d i u s R

a n d t a n g e n t b y s i d e s A B a n d B C o f

t r i a n g l e ?

Answered by $@y@m last updated on 04/Oct/20

T h e c e n t r e o f t h e c i r c l e i s I n c e n t r e o f

△ A B C a n d r a d i u s o f c i r c l e i s g i v e n b y

R = \frac{△}{s}

w h e r e △ = A r e a o f △ A B C

a n d s = s e m i p e r i m e t e r

Commented by $@y@m last updated on 04/Oct/20

S o r r y . I j u s t r e m e m b e r t h e f o r m u l a

r e a d i n m y t e x t b o o k .

I {d o n}^{'} t r e m e m b e r t h e p r o o f .

P l e a s e g o t h r o u g h t h e c o n c e p t o f I n c i r c l e

i n y o u r t e x t b o o k .

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