Question Number 116520 by kaivan.ahmadi last updated on 04/Oct/20
$${find}\:{the}\:{center}\:{of}\:{circle}\:{with}\:{radius}\:{R} \\ $$$${and}\:{tangent}\:{by}\:{sides}\:{AB}\:{and}\:{BC}\:{of}\: \\ $$$${triangle}? \\ $$
Answered by $@y@m last updated on 04/Oct/20
$${The}\:{centre}\:{of}\:{the}\:{circle}\:{is}\:{Incentre}\:{of} \\ $$$$\bigtriangleup{ABC}\:{and}\:{radius}\:{of}\:{circle}\:{is}\:{given}\:{by} \\ $$$${R}=\frac{\bigtriangleup}{{s}} \\ $$$${where}\:\bigtriangleup={Area}\:{of}\:\bigtriangleup{ABC} \\ $$$${and}\:{s}={semi}\:{perimeter} \\ $$
Commented by $@y@m last updated on 04/Oct/20
$${Sorry}.\:{I}\:{just}\:{remember}\:{the}\:{formula} \\ $$$${read}\:{in}\:{my}\:{textbook}. \\ $$$${I}\:{don}'{t}\:{remember}\:{the}\:{proof}. \\ $$$${Please}\:{go}\:{through}\:\:{the}\:{concept}\:{of}\:{Incircle} \\ $$$${in}\:{your}\:{textbook}. \\ $$